7(x+1)=4[x-3(3-x)]

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Solution for 7(x+1)=4[x-3(3-x)] equation:


Simplifying
7(x + 1) = 4[x + -3(3 + -1x)]

Reorder the terms:
7(1 + x) = 4[x + -3(3 + -1x)]
(1 * 7 + x * 7) = 4[x + -3(3 + -1x)]
(7 + 7x) = 4[x + -3(3 + -1x)]
7 + 7x = 4[x + (3 * -3 + -1x * -3)]
7 + 7x = 4[x + (-9 + 3x)]

Reorder the terms:
7 + 7x = 4[-9 + x + 3x]

Combine like terms: x + 3x = 4x
7 + 7x = 4[-9 + 4x]
7 + 7x = [-9 * 4 + 4x * 4]
7 + 7x = [-36 + 16x]

Solving
7 + 7x = -36 + 16x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16x' to each side of the equation.
7 + 7x + -16x = -36 + 16x + -16x

Combine like terms: 7x + -16x = -9x
7 + -9x = -36 + 16x + -16x

Combine like terms: 16x + -16x = 0
7 + -9x = -36 + 0
7 + -9x = -36

Add '-7' to each side of the equation.
7 + -7 + -9x = -36 + -7

Combine like terms: 7 + -7 = 0
0 + -9x = -36 + -7
-9x = -36 + -7

Combine like terms: -36 + -7 = -43
-9x = -43

Divide each side by '-9'.
x = 4.777777778

Simplifying
x = 4.777777778

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